Help: count even and odd numbers

[taigaicon]

Hi, I just picked a book recently and try to teach myself C, so I am new to this.

The problem I am trying to solve is to write a program that reads integers until 0 is entered.
And then, terminates the program and count even(exclude 0) and odd numbers as well as their averages.

Below is my code. It's working, but what I don't understand is that if I use even_count instead of (even_count-1), I will have 1 more even number than I wanted. Can someone please let me know if my logic is wrong?

#include <stdio.h>

int main(void)
{
    int num,a;
    
    int even_count = 0;
    int odd_count = 0;
    int even_sum = 0;
    int odd_sum = 0;

    
    
    while (num !=0)
    {
          printf("Please enter a number (0 to stop):\n");
          a = scanf("%d", &num);
          
          if (a = 0)
             goto terminate;
          
          else
          {
              if ( (num%2)!=0)
              {
                   odd_count++;
                   odd_sum = num +odd_sum;
              }
              else
              {
                  even_count++;
                  even_sum += num;
              }
          }
    }
    
    terminate: printf("prgram terminated.\n\n");
   
    printf("odd count: %d ; even count: %d\n", odd_count, even_count-1);              
    printf("odd sum: %d ; even sum: %d\n", odd_sum/odd_count, even_sum/(even_count-1));
    
    
             
    system ("pause");
    return 0;
}

[anduril462]

There are a few problems:
You should avoid using goto. There are exceptions, but this isn't one of them.

You need to use == for comparison, = for assignment. The result of if (a = 0) is whatever a is. You assign a to zero, so you always end up in the if block. Try

if (a == 0)
    break;
else
    ...

If somebody enters 0 for num, you still check for odd or even and increment the count. Since 0 % 2 is 0, you increment even_count. Try:

if (a == 0)
    break;
else if (num != 0)
{
    if ( (num%2)!=0)
    {
        odd_count++;
        odd_sum = num +odd_sum;
    }
    else
    {
        even_count++;
        even_sum += num;
    }
}