Need help, I'm a begginer!

[JonathanPoll]

Hello all,

As you may see, I am new to this forum.
I started programming a little while ago, I'm not that good yet, still can't understand pointers, or insert pictures, but I do exercise by making loads of programs.

I am trying to make a program that will find me all the dividers of a certain number.
I get an error message saying "Error: too few arguments to function "etape1""
Can anyone please find my error?

Here is my source code:


#include <stdio.h>
#include <stdlib.h>
#include <math.h>

// Trouve TOUT les diviseurs d'un nombre.

int etape1(int divise, int nombreEntre, int resultat)
{
do
{
if (nombreEntre%divise == 0);
{
printf("%d\n", divise);
}
divise++;
} while (divise < nombreEntre);
return 0;
}


int main(int argc, char *argv[])
{

int nombreEntre = 0, resultat = 0;
printf("Entrez un nombre pour voir tout ses diviseurs\n ");
scanf("%d", &nombreEntre);
resultat = etape1(nombreEntre); Edit: This is where the error is.
return 0;
}


Thanks a lot, Jonathan Poll

[TheBigH]

When you call etape1 near the end of your program, you are only giving it nombreEntre. It expects three arguments, namely divise, nombreEntre, and resultat.

[CommonTater]

Look at the definition of the function ...

int etape1(int divise, int nombreEntre, int resultat)

and the way you are calling it...

resultat = etape1(nombreEntre);

Now... do you see anything wrong with that picture?
(hint: Listen to your compiler's error message)

[JonathanPoll]

Look at the definition of the function ...

int etape1(int divise, int nombreEntre, int resultat)

and the way you are calling it...

resultat = etape1(nombreEntre);

Now... do you see anything wrong with that picture?
(hint: Listen to your compiler's error message)

Thanks both of you for the quick replies!

Yes, I do see the error, also helps that the previous replier answered

Thanks a lot both of you