Help! Warning: Initialization makes integer from pointer without a cast

This is a discussion on Help! Warning: Initialization makes integer from pointer without a cast within the C Programming forums, part of the General Programming Boards category; I am writing a program and in line 50 it marks me this: Warning: Initialization makes integer from pointer without ...

  1. #1
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    Help! Warning: Initialization makes integer from pointer without a cast

    I am writing a program and in line 50 it marks me this: Warning: Initialization makes integer from pointer without a cast. How do I fix it? The problem started when I had to create a loop to ask whether yes or no if the user would like to calculate another trip. I do not know how to fix. Please help.

    Code:
    #include <stdio.h>
    
    int main(void)
    
    {
       
       float numP, numL, HalfCost, EachLcost, TotalHalf, TotalCost, ans;
       int loop;   
    
       printf("\nPlease enter the number of passengers. Children under the age 12 are represented by .5: ");
     
       scanf("%f",&numP);
    
       if (numP<0 )
    	numP=3;
       else
            printf ("%f",numP);
       
       printf ("\nHow many legs the trip has to get to the destination?");
       scanf("%f",&numL);
       TotalHalf = 0;
    
       loop=1;
       while (loop <= numL){ 
    
          printf("\nWhat is the price of leg %d?",loop);
          scanf("%f",&EachLcost);
          TotalHalf =TotalHalf + EachLcost;
          loop++;
    }
       printf("\nThe total cost for half the trip is:");
    
       if(TotalHalf>0)
    	printf("%f",TotalHalf);
       
          
       TotalCost=TotalHalf*2;
       printf("\nThe round trip cost for one person is: $ %f",TotalCost);
       
       printf("\nThe round trip cost for %f persons is: $ %f",numP, TotalCost*numP);
    
    
      // return TotalCost*numP;
        
       printf("\nWould you like to calculate another trip cost? (Y/N)?");
       scanf("%c",&ans);
       
       if(ans == 'Y')
         return main;
    
       else(ans== 'N');
         printf("\nThank You!");
    
       return TotalCost*numP;   
    }
    Attached Files Attached Files
    Last edited by Salem; 02-09-2011 at 12:21 AM. Reason: Added [code][/code] tags - learn to use them yourself

  2. #2
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    change ans to a char (it's a float now).

    Right after the scanf("%c", &answ);

    add this:

    getchar();

    to remove the newline char that scanf() leaves behind on the keyboard stream.
    Code:
    if(ans == 'Y')
    return main;
    is bad code - make it a loop, also (nested, with the one you have now).
    Last edited by Adak; 02-08-2011 at 08:41 PM.

  3. #3
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    Quote Originally Posted by Adak View Post
    Code:
    if(ans == 'Y')
    return main;
    is bad code - make it a loop, also (nested, with the one you have now).
    Hey, calling main.... always a good way to blow up the stack...

  4. #4
    and the hat of wrongness Salem's Avatar
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    > return main;
    This is a function pointer
    What you're doing is returning the address of main, not calling main.
    And since this is a pointer, and main expects to return an int, this is why you're getting a "integer from pointer" error message.

    return main();
    Now this would call main recursively, and as noted would be a bad thing to do.

    If you want a loop, do this
    Code:
    do {
      // your code you want to repeat
    } while ( ans == 'y' );
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.
    I support http://www.ukip.org/ as the first necessary step to a free Europe.

  5. #5
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    Thank you all very much for all your help.

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