Thread: How to access data from a Linked List?

Hi!

I believe it must be quite simple to do, and I'm not finding it on the forum. I'd like to access a specific variable in my code which is in a Linked List.

I've tried to use something like struct_name[position].variable_name, but It's not working. On the code below, I tried to print its value...

What am I supposed to do?

Code:

#include <stdio.h>
#include <stdlib.h>


struct list {
    int info;
    struct list* next;
};
   
typedef struct list List;

List* initialize (void)
{
     return NULL;
}
    
List* insert (List* l, int i)
{
       List* new = (List*) malloc(sizeof(List));
       new->info = i;
       new->next = l;
       return new;
 }
    
void print (List* l)
 {
       List* p;   
       for (p = l; p != NULL; p = p->next)

            printf("info = %d\n", p->info);
 }
    
int main(int argc, char *argv[])
{
    
    l = initialize();  
    l = insert(l, 23); 
    l = insert(l, 45);
  
     print(l);
     printf("%d\n",l[0].info); //<------------------------ Here
  

     system("PAUSE");    
     return 0;

Thanks =)

uhmm

So the only way is to use a loop to access one by one...
Thanks for your explanation, alecodd!

This code is not mine, actually. That's why one print routine works and the another one doesn't. I'm using it to understand how all this stuff work, and than work on my project =)