When I run this, the 1st print statement prints out a >, yet the if gets evaluated to false and the inside print does not execute. wtf?
edit: I tried single and double quotes around the >Code:printf(command.argv[argc1 - 2]); if(command.argv[argc1 - 2] == '>') { printf("blah"); }
Perhaps a little more code that we can compile and fiddle with would help a bit. Because
if(command.argv[argc1 - 2] == '>')
just doesn't look right to me.
>printf(command.argv[argc1 - 2]);
This isn't right, if I'm correct and you're using names for your structure members that are already identified with being arguments to main, and you're trying to print a single character, it should be like this:
printf ( "%c", command.argv[argc1 - 2] );
If you're working with the arguments to main then you're way off.
-Prelude
My best code is written with the delete key.
Actually, I'm not using args to main. It's a simple shell program , and command is a struct that holds the parsed command line that was entered by the user. I changed it a little bit, so I use this for loop to examine the contents of the argv array:
Then here is the full if statement:Code:for(k = 0; command.argv[k] != NULL; k++) printf("Arg %i : %s\n", k, command.argv[k]);
The for loop outputs this:Code:for(k = 0; command.argv[k] != NULL; k++) if(command.argv[k] == '>') { printf("DFSDF"); redirectOut = TRUE; command.argv[k] = '\0'; filename = command.argv[k+1]; command.argv[k+1] = '\0'; }
Arg0: ls
Arg1: >
Arg2: textfile
Yet the if statement is never entered. I am befuddled.
>if(command.argv[k] == '>')
This won't work because argv[k] is a string. Strings cannot be compared in C with the == operator, you have to use strcmp.
-PreludeCode:if ( strcmp ( command.argv[k], ">" ) == 0 )
My best code is written with the delete key.
Doh, I feel stupid now. Thanks for your help.
