c program problem

the program compiles fine by it doesn't run as it should
any idea what might be wrong?

Code:

			case 1: /*selection 1 easy*/
				
				i1 = rand() % 100;
				i2 = rand() % 100;
				i3 = rand() % 100;
				
				printf("\nConcentrate on the next three numbers:\n"); /*this line is printed but then clear_screen() function activates*/
				printf("\n%d\t%d\t%d", i1, i2, i3); /*then this line is printed which should be cleared along with the one above*/
				
				iCurrentTime = time(NULL);
				do 
				{
					iElapsedTime = time(NULL);
				} while ( (iElapsedTime - iCurrentTime) < 4 ); /*end do while*/
				
				clear_screen();
				
				printf("\nEnter each number separated with one space: "); /*along with the numbers this line is also printed...*/
				scanf("%d%d%d", &iResp1, &iResp2, &iResp3);
				
				if (iResp1 == i1 && iResp2 == i2 && iResp3 == i3)
					
						printf("\nCongratulations!");
					else
						printf("\nSorry, correct numbers were: %d %d %d", i1, i2, i3);
					 /*end if*/

Is this for a "bulls and cows" game or what?

Exactly what is it doing wrong?

> printf("\n%d\t%d\t%d", i1, i2, i3);
Since this line does not end with a \n, you should call fflush(stdout) to ensure that the data is displayed.

Otherwise, the output will remain buffered until after the screen has been cleared.

well you have to remember those 3 numbers in 3 seconds
they they "should" be cleared
and you have to enter them correctly

but they don't get cleared so the game is pointless

Originally Posted by Salem

> printf("\n%d\t%d\t%d", i1, i2, i3);
Since this line does not end with a \n, you should call fflush(stdout) to ensure that the data is displayed.

Otherwise, the output will remain buffered until after the screen has been cleared.

thanks it worked