Function for chek if letter exist

[lio]

Hi ,I wrote this functiont to check for abanded characters ,but it doesnt work
I need help
Thanks
The errors are missing terminating characters

int checkout(char letter)
{
  char forbiden[20]={'{','}','[',']','(',')','0','1','2','3','4','5','6','7','8','9','+,'-','*','/'};
  int i;
  int numErrors=0;
  for(i=0;i<20;i++)
  {
    if(forbiden[i]!=letter);
    numErrors++;
  }
  return numErrors;
}

[CommonTater]

Try it like this....

int checkout(char letter)
{
  char forbiden[21]={"{}[]()0123456789+-*/\0"};
  int i;
  int numErrors=0;
  for(i=0;i<20;i++ )  
   {
    if(forbiden[i] == letter)
    numErrors++;
  }
  return numErrors;
}

[Salem]

It doesn't work, because it doesn't compile - your if statement is broken.

[lio]

Thanks,
Common tater
I pasted your code agin and it works

[Salem]

It's no use saying "an error", you need to post actual error messages.

[CommonTater]

Thanks,
Common tater
I pasted your code agin and it works

Now... do yourself the favor of spending a minute and figuring out WHY it works...