Differnce between uint16_t and an uint8 array

Hi, can some one explain to me the difference between

Code:

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uin16_t

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and an

Code:

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uint8_t array[2]

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Thanks.

It would probably be easier to list the similarities:

• They are the same size.

They differ in pretty much every other respect.

Thanks, so what is the better choice to store

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2 BCD bytes

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an

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uint16_t

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or an

Quote:

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unit8_t array[2]

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?

2 uint8_t, because you have a byte, which is uint8_t and 2 of them.
When you use bigger sizes, you have to deal with endianess. But if you use an array, you don't.

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Originally Posted by Elysia

2 uint8_t, because you have a byte, which is uint8_t and 2 of them.
When you use bigger sizes, you have to deal with endianess. But if you use an array, you don't.

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Thanks for the reply, it's ok for me.

2 BCD bytes? Don't you mean 2 BCD nibbles? It would only take one byte to store.

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Originally Posted by evariste

Thanks for the reply, it's ok for me.

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That makes no sense whatsoever.

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Originally Posted by nonoob

2 BCD bytes? Don't you mean 2 BCD nibbles? It would only take one byte to store.

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NO I mean 2 BCD Bytes.

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Originally Posted by Elysia

That makes no sense whatsoever.

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yes it make sense because i don't want to deal with endianess :)