Thread: reading file then if statement not working

I've been having a little problem with grabbing a word from a file then checking it using an if statement to see if it is true or not.
when the code reaches the "printf("Line = ...." it prints out the variable, which is the first string then the second string, but when the if statement comes in, even though it the exact same that it is in the data file, it turns out to be false and doesn't execute.

this is the concept code:

Code:

#include <stdio.h>
#include <stdlib.h>
int main()
{
	FILE * in = fopen("DATA.txt", "r");
	char line[255];
	if (in == NULL)
	{
		printf("The input file was not found, or an error occured while reading the file");
		return 1;
	}
	else
	{
		while (!feof(in))
		{
			fscanf(in, "%s", line);
			printf("Line = %s\r\n", line); /* this was here to debug */
			if (line == "Test:")
			{
				fscanf(in, "%s", line);
				if(line == "True")
				{
					printf("This is a test");
					getchar();
				}
				else
				{
					printf("This is not a test");
					getchar();
				}
			}
		}
	}
	return 0;
}

and the data file is

Code:

Test: True

I know, it was declared as an array, but the variable, line, oddly enough, is treated by the compiler as though it were a pointer.
Cprogramming.com FAQ > Pointers And Arrays (intermediate)

To get around this you could dereference the "pointers" one at a time and compare them, or use strcmp as quzah says, that's what strcmp does.

The string literal, "True" can also be treated as though it were a pointer (because it is)...

Code:

if *line == *"T" && *(line+1) == *"r" && *(line+2) == *("True" + 2) ...
if line[0] == 'T' && line[1] == 'r' && 2[line] == 2["True"] ...

Also, don't use feof to control your loop: Cprogramming.com FAQ > Why it's bad to use feof() to control a loop.