Segmentation Fault

[waxman83]

Hey all,

I had previous question that was expertly answered today, and now I have another issue. I am trying to display the values I entered into a dynamic 2-dimensional array, but when my code gets to the display loop, I get a segmentation fault. My code so far is below.

#include<stdio.h>
#include<math.h>
#include<stdlib.h>

main()  {
        int i, j;

        double *CellPtr;

        //values to hold row & col size for array & mem size needed
        int col, row, Doubles;

        printf("\nEnter the number of columns desired for your array \n");
        scanf("%d", &col);

        printf("\nEnter the number of rows desired for your array \n");
        scanf("%d", &row);

        Doubles = col * row;

        //declaring the array
        double **ArrayPtr;
        ArrayPtr = malloc(row * sizeof(double *));

        for(i = 0; i < row; i++)
                ArrayPtr[i] = malloc(col * sizeof(double));

        //filling the array with the requested values
        for(i = 0; i < row; i++)
                for(j = 0; j < col; j++)        {
                        *ArrayPtr = (int) i * 100 + j;
                        ArrayPtr++;
                }

        //THIS IS GIVING ME THE PROBLEM
        for(i = 0; i < row; i++)
                for(j = 0; j < col; j++)
                        printf("%d\n", ArrayPtr[i][j]);
}

I hope it's OK to include the whole program; it's pretty small.

If anyone could let me know why I'm getting the segmentation fault (or if there's a glaring, horrific error in my display code logic), I'd really appreciate it.

Thanks in advance!

[tabstop]

You moved your ArrayPtr hither and yon throughout the thickets of your doubly-subscripted array. Now: how are you going to get it back?

(EDIT: And for bonus fun: who says your doubly-subscripted array is all stored in order?)

[Salem]

> printf("%d\n", ArrayPtr[i][j]
You should have used this notation to write to the array.

You also need to look up how to use printf as well - %d is not for doubles.