ATM in C, what's the bug?

This is a discussion on ATM in C, what's the bug? within the C Programming forums, part of the General Programming Boards category; okay, so i need to make a stimulated ATM in C for my programming class, i've made it, but it ...

  1. #1
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    Dec 2010
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    7

    Question ATM in C, what's the bug?

    okay, so i need to make a stimulated ATM in C for my programming class, i've made it, but it doesn't run the whole code properly, it stops at wherever there the 2nd scanf is.
    here my code:

    Code:
    #include <stdio.h>
    #include <stdlib.h>
    
    int p(balance){
    	char option, trans, secop, secopd;
    	do{
    	printf("what transaction would you like to do\n");
    	printf("    W-Withdraw          D-Deposit\n");
    	printf("    C-Check Balance     P-Pay bills\n");
    	printf("    Q-Quit\n\n");
    	scanf("%c", &option);
    	if (option=='w'){
    		printf("what's your withdraw amount?\n");
    		printf("    A $20.00    D $80.00\n");
    		printf("    B $40.00    E $100.00\n");
    		printf("    C $60.00    F Cancel\n");
    		scanf("%c", &secop);
    		if(secop=='a'){
    			printf("$20.00 withdrawn\n");
    			balance-20;
    			printf("would you like to make another transaction?[Y/N]\n");
    			scanf("%c", &trans);
    			if(trans=='n'){
    				return balance;
    			}
    		}
    		if(secop=='b'){
    			printf("$40.00 withdrawn\n");
    			balance-40;
    			printf("would you like to make another transaction?[Y/N]\n");
    			scanf("%c", &trans);
    
    			if(trans=='n'){
    				return balance;
    			}
    		}
    		if(secop=='c'){
    			printf("$60.00 withdrawn\n");
    			balance-60;
    			printf("would you like to make another transaction?[Y/N]\n");
    			scanf("%c", &trans);
    
    			if(trans=='n'){
    				return balance;
    			}
    		}
    		if(secop=='d'){
    			printf("$80.00 withdrawn\n");
    			balance-80;
    			printf("would you like to make another transaction?[Y/N]\n");
    			scanf("%c", &trans);
    
    			if(trans=='n'){
    				return balance;
    			}
    		}
    		if(secop=='e'){
    			printf("$100.00 withdrawn\n");
    			balance-100;
    			printf("would you like to make another transaction?[Y/N]\n");
    			scanf("%c", &trans);
    
    			if(trans=='n'){
    				return balance;
    			}
    		}
    		if(secop=='f'){
    			return balance;
    		}
    	}
    
    	if (option=='d'){
    			printf("what's your deposit amount?\n");
    			printf("    A $20.00    D $80.00\n");
    			printf("    B $40.00    E $100.00\n");
    			printf("    C $60.00    F Cancel\n");
    			scanf("%c", &secopd);
    			if(secopd=='a'){
    				printf("$20.00 deposited\n");
    				balance+20;
    				printf("would you like to make another transaction?[Y/N]\n");
    				scanf("%c", &trans);
    
    				if(trans=='n'){
    					return balance;
    				}
    			}
    			if(secopd=='b'){
    				printf("$40.00 deposited\n");
    				balance+40;
    				printf("would you like to make another transaction?[Y/N]\n");
    				scanf("%c", &trans);
    
    				if(trans=='n'){
    					return balance;
    				}
    			}
    			if(secopd=='c'){
    				printf("$60.00 deposited\n");
    				balance+60;
    				printf("would you like to make another transaction?[Y/N]\n");
    				scanf("%c", &trans);
    
    				if(trans=='n'){
    					return balance;
    				}
    			}
    			if(option=='d'){
    				printf("$80.00 deposited\n");
    				balance+80;
    				printf("would you like to make another transaction?[Y/N]\n");
    				scanf("%c", &trans);
    
    				if(trans=='n'){
    					return balance;
    				}
    			}
    			if(secopd=='e'){
    				printf("$100.00 deposited\n");
    				balance+100;
    				printf("would you like to make another transaction?[Y/N]\n");
    				scanf("%c", &trans);
    
    				if(trans=='n'){
    					return balance;
    				}
    			}
    			if(option=='f'){
    				return balance;
    			}
    		}
    
    	if(option=='c'){
    		printf("%i", balance);
    		printf("\nwould you like to make another transaction?[Y/N]\n");
    		scanf("%c", &trans);
    		if(trans=='n'){
    			return balance;
    		}
    	}
    	if(option=='p'){
    		int account, amount;
    		printf("\nplease enter the account's number that you wish to pay your bills to:\n");
    		scanf("%i", &account);
    		printf("how much is your bill?\n");
    		scanf("%i", &amount);
    		printf("$%i.00 is paid to %i", amount, account);
    		printf("would you like to make another transaction?[Y/N]\n");
    		scanf("%c", &trans);
    		if(trans=='n'){
    			return balance;
    		}
    	}
    	if (option=='q'){
    		return balance;
    	}
    	}
    	while(trans=='y');
    	return balance;
    }
    
    int main(void) {
    	int balance;
    	balance = rand() % 500 + 270;
    	printf("    ++++++++\n");
    	printf("    +RBNWSS+\n");
    	printf("    ++++++++\n");
    	p(balance);
    	return 0;
    }
    so what's my error, i've removed a lot of code in order for it to run, for example, it's suppose to ask the user for there pin, and it should only proceed if the pin entered is 1234, but with the pin code in place, if statements seems to loose its function.

    help would be greatly appreciated

  2. #2
    Programming Wraith GReaper's Avatar
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    Each time you're getting a char from the console. But each time you leave '\n' in the console buffer. So when your next scanf is called, it doesn't wait for the user because it finds data in the buffer to read. That data is most likely '\n', that's why it stops.
    Devoted my life to programming...

  3. #3
    Registered User
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    Quote Originally Posted by Sipher View Post
    Each time you're getting a char from the console. But each time you leave '\n' in the console buffer. So when your next scanf is called, it doesn't wait for the user because it finds data in the buffer to read. That data is most likely '\n', that's why it stops.
    what? isn't \n equivalent to <br> in in html?
    it just means change line, how can is mess up anything?

  4. #4
    ATH0 quzah's Avatar
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    Quote Originally Posted by evo85210 View Post
    what? isn't \n equivalent to <br> in in html?
    it just means change line, how can is mess up anything?
    Code:
    #include<stdio.h>
    int main( void )
    {
        int c;
        do
        {
            printf( "enter a character, or q to quit\n" );
            c = getchar();
            printf( "you entered \'%c\'", c );
        }
        while( c != 'q' );
        return 0;
    }
    That's how.


    Quzah.
    Hope is the first step on the road to disappointment.

  5. #5
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    Quote Originally Posted by evo85210 View Post
    what? isn't \n equivalent to <br> in in html?
    it just means change line, how can is mess up anything?
    Because it is sitting unprocessed in the input buffer.

  6. #6
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    Yet another cross-poster

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