Passing array into function

I am trying to write a program that will compute an angle and magnitude of a given complex number. I have therefore declared an array of 2 floats in which [0] stores the real part and [1] the imaginary part. My code looks as follows:

Code:

#include <stdio.h>
#include <math.h>

float magnitude(float c[]);

void arc(float c, int *arcn);

int main()
{
	float complex[2];
	float owned;

	printf("Enter real part > ");
	scanf("%f", &complex[0]);
	printf("Enter imaginary part > ");
	scanf("%f", &complex[1]);

	printf("Magnitude: %f", magnitude(complex));
	arc(complex, &owned);
	printf("Angle: %f", owned);
}

float magnitude(float c[])
{
	float temp;

	temp = sqrt(c[0]*c[0] + c[1]*c[1]);

	return temp;
}

void arc(float c[], float *arcn)
{
	*arcn = atan(c[1]/c[0]);
}

However I am getting an error:

Code:

main.c(19) : error C2440: 'function' : cannot convert from 'float [2]' to 'float'

What is wrong with the program? Please help.

I know I could use a return statement in the second function, but I do not want to. The whole purpose of this program is to excercise functions which return a value, and which manupulate values passed by a pointer.

You've defined arc() to accept a single float value as the first arg, not an array of floats.

changed this line

Code:

void arc(float c, int *arcn);

to

Code:

void arc(float *c, int *arcn);