Thread: switch () {default: <something>; case ...

Consider the following:

Code:

#include <stdio.h>


int main(void)
{
        int i = 3;

        switch (i){
                default:
                        i = -1;
                        break;
                case 1:
                case 2:
                case 3:
                        i = 5;
                        break;
        }

        printf ("i = %i.\n", i);
        return 0;
}

Output is:
i = 5.

Is this a definition of the standard, or is this compiler specific (ie, gcc). This code example is one that I tried and it works as if the default was at the end, but I would think it would match the default FIRST and never test against 1,2,3.

The code that coRnfused me was from the Linux kernel in the file kernel/posix-cpu-timers.c.

Thanks in advance for your answers.

Andy

Hmm, so then everyone that I polled here believed it to be a syntax error, however, it worked, based upon the standard. So, this leads me to believe that near everyone is taught that default must come at the end, which is erroneous.

Yet again, I have found something I was taught to be fact as false.

Bummer man.

Thanks laserlight!

Andy