Returned from strstr() and pointers...

[towed]

I am searching for a specific word in a sentence and check for it using strstr(). Then check the return of it to see if it returns NULL to continue onward. Finally, check to see if first char is a "space" and if so, change it to "9". MY question is, from what is returned (the base address of the substring of that sentence and what was after it), how can I copy that to another string to use it.

So far...

     char *ptr, *ptr_str;
     char *segment[5];

/* Omit code for ease. */

     ptr = strstr(string, segment[i]);

     if(ptr != NULL){

        printf("---> Residual part of the string was %s\n", ptr);

        ptr_str = malloc(sizeof(ptr) + 1);
        strcpy(ptr_str, ptr);
        printf("Returned from first successful strstr call is: %s.\n",
                  ptr_str);

/*     See if their is an space present in the present wx group and 
        truncate/remove it if necessary. */

        if(ptr_str[0] == " ") ptr_str[0] = "9"; /* Assign the first character to a random in -- "9"; */

I get compile error:
array_search_strstr.c:warning: comparison between pointer and integer
array_search_strstr.c:warning: assignment makes integer from pointer without a cast

Confusing as it prints out the residual part in the print statement...

Any idea?

[Bayint Naung]

ptr_str = malloc(sizeof(ptr) + 1); // WRONG!
You need to use strlen() function. not sizeof operator. sizeof(ptr) ,in this case, will give you the size of pointer.ie sizeof(char*) sizeof a char pointer. usually 2 or 4 bytes.

        if(ptr_str[0] == " ") ptr_str[0] = "9"; /* Assign the first character to a random in -- "9"; */

To compare C strings, you need to use strcmp() function.
In your case, you can just check whether the first char is
Edit: space (' ') char/ if( ptr_str[0] == ' ' )
ptr_str[0] type is char. and "9" is a string literal.
Change it to ptr_str[0] = '9'; // '9' is char literal.

[towed]

(explicative) Im embarrass to say that I didn't catch those two...

[Jesius]

"" is a string literal, include '\0' at the end.