Thread: How can I compare strings?

Whats an easy way to compare arg1 with arg2
and if arg1 only contains one letter and it that matches arg2's first letter
then it returns 1 and if arg1 contains more than one character
that all match arg 2 it returns one otherwise it returns zero?

Code:

int is_abbrev(const char arg1, const char arg2)
{
  if (!*arg1)
    return (0);

  for (; *arg1 && *arg2; arg1++, arg2++)
    if (LOWER(*arg1) != LOWER(*arg2))
      return (0);

  if (!*arg1)
    return (1);
  else
    return (0);
}

I basically just want acopy of the above that returns one if arg1 only has one character and that character matches arg2's first character. thanks.

Code:

int is_abbrev(const char *arg1, const char *arg2)
{
  if (!*arg1)
    return (0);

  for (; *arg1 && *arg2; arg1++, arg2++)
    if (LOWER(*arg1) != LOWER(*arg2))
      return (0);

  if (!*arg1)
    return (1);
  else
    return (0);
}

I want the above code to return one even if the strings match at the first character and arg one has no other character than the first character.

So if I understand correctly, if the entire string in arg1, whether it's 1 character or several characters, is the same as the beginning of arg2, then return 1. Otherwise return 0.

If that's the case, then you should use the strncmp function as I described, with one very minor modification. strncmp is going to return zero if they match up to the n characters, so you need to adjust your is_abbrev function accordingly.

directions[]]= { "north",
"east",
"south",
"west",
"up",
"down" };

I just want to be able to open n and all i need is for the is_abbrev function to return 1 if the value n is passed to agument. same for n e w s u d. But the is_abbrev function +
+ plusseses I think before its first comparison. but c progrmmaing mus be understood to modify that function.

Code:

int find_door(struct char_data *ch, const char *type, char *dir, const char *cmdname)
{
  int door;
  char *directions[] = {"north", "east", "south" , "west" , "up", "down"};

  if (*dir) {			/* a direction was specified */
    if ((door = search_block(dir, dirs, FALSE)) == -1) {	/* Partial Match */
      send_to_char(ch, "That's not a direction.\r\n");
      return (-1);
    }
    if (EXIT(ch, door)) {	/* Braces added according to indent. -gg */
      if (EXIT(ch, door)->keyword) {
	if (isname(type, EXIT(ch, door)->keyword))
	  return (door);
	else {
	  send_to_char(ch, "I see no %s there.\r\n", type);
	  return (-1);
        }
      } else
	return (door);
    } else {
      send_to_char(ch, "I really don't see how you can %s anything there.\r\n", cmdname);
      return (-1);
    }
  } else {			/* try to locate the keyword */
    if (!*type) {
      send_to_char(ch, "What is it you want to %s?\r\n", cmdname);
      return (-1);
    }
    for (door = 0; door < NUM_OF_DIRS; door++)
      if (EXIT(ch, door))
	if (EXIT(ch, door)->keyword)
	  if (isname(type, EXIT(ch, door)->keyword) || is_abbrev(type, directions[door]))
	    return (door);

    send_to_char(ch, "There doesn't seem to be %s %s here.\r\n", AN(type), type);
    return (-1);
  }
}


int is_abbrev(const char *arg1, const char *arg2)
{
  if (!*arg1)
    return (0);

  for (; *arg1 && *arg2; arg1++, arg2++)
    if (LOWER(*arg1) != LOWER(*arg2))
      return (0);

  if (!*arg1)
    return (1);
  else
    return (0);
}

I just need a function simular to is_abbrev that will return one if n e s w u or d is passed to it.

Or mayby a new function that will do what is_abbrev isn't. The other function parses argument. I just need something simular to is_abbrev that recognizes only one character as an abbreviation of argument two. If only one character was used. I just put the other function there to show how is_abbrev is being used.