Thread: how to name an array? and call an array?

  1. #1
    Registered User l2krence's Avatar
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    Post how to name an array? and call an array?

    Well, how to actually tis array
    Code:
    for(x=0;x<6;x++){
       for(y=0;y<6;y++){
       printf(" # ");
       }
    }
    i want to call tis array to like having (array) and set it's position of [0][0] to be a certain value.

    so how to call tis array and set it to like ,,, (array)[0][0] = '!';

  2. #2
    C++ Witch laserlight's Avatar
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    What array are you talking about?
    Quote Originally Posted by Bjarne Stroustrup (2000-10-14)
    I get maybe two dozen requests for help with some sort of programming or design problem every day. Most have more sense than to send me hundreds of lines of code. If they do, I ask them to find the smallest example that exhibits the problem and send me that. Mostly, they then find the error themselves. "Finding the smallest program that demonstrates the error" is a powerful debugging tool.
    Look up a C++ Reference and learn How To Ask Questions The Smart Way

  3. #3
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    Quote Originally Posted by l2krence View Post
    Well, how to actually tis array
    Code:
    for(x=0;x<6;x++){
       for(y=0;y<6;y++){
       printf(" # ");
       }
    }
    i want to call tis array to like having (array) and set it's position of [0][0] to be a certain value.

    so how to call tis array and set it to like ,,, (array)[0][0] = '!';
    You answered your question right in your own question...

    Code:
    int array[6][6];
    
    for(x=0;x<6;x++){
       for(y=0;y<6;y++){
          array[x][y] = 0;
          printf(" %d ",array[x][y]);
         }
    }
    just like you said...

  4. #4
    Lurking whiteflags's Avatar
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    There is a class of pointer types where the grouping is significant.

    For example:
    Code:
    int array[12]
    int (*ptr)[12] = &array;
    Sometimes wrapping things in parentheses means nothing and at other times it is all the difference in type. Careful, there.

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