Bitwise input/output

[dhuan]

I'm reading about bit input/output on this link:
Bit input/output

It says:

AND, if the bit from the second parameter is 1, the bit from the first one is not modified. If it's 0, it will be changed to 0. We use to clear bits we don't care about.

But then:

For example if we only care about the rightmost bit, but the other ones could be non zero, we use AND. "011010" AND "000001", result: "000001".

So...

011010
000001
---------
000001


Am I missing something? How come 0&1 is 1 is it's been stated that "if the bit from the second parameter is 1, the bit from the first one is not modified."?

oh and btw, sorry if this is the wrong section to post it

[gaurav9991]

you are correct, I'm agree with you

[CommonTater]

Am I missing something? How come 0&1 is 1 is it's been stated that "if the bit from the second parameter is 1, the bit from the first one is not modified."?

oh and btw, sorry if this is the wrong section to post it

It would be correct if the second logic operation was an OR.

FWIW... you can be fairly sure your lessons are sinking in when you start finding errors in the course materials.

[Bennie98]

It would be correct if the second logic operation was an OR.

that's what the course also says...

For example if we have the binary value "0010" and OR it with "1110" we get "1110".

First parameter 0110
Second parameter 1010
Result 1110

so the course is actually contradicting itself

[CommonTater]

so the course is actually contradicting itself

Believe me this wouldn't be the first time I've found errors in coursewares.

Of course 011010 AND 000001 = 0.

As I said before it speaks well of your learning process that you caught it.