help

[mouse666666]

why is this not printing anything on the screen

#include<stdio.h>
#include<conio.h>

int fun1 (int a[], int *b);

main()
 {
      char name[15]={'j','o','h','n'};
      char *ptr[3];
              
      ptr[1]=name;
      printf("%c", *(ptr+2));   
                         getch();
};

[Elysia]

Why do you think it will? *(ptr + 2) is not initialized (otherwise known as ptr[2]).
Furthermore, as you see, you are trying to print a string (char*) with %c.
And finally, choose a proper subject next time. Not just "help".

[Adak]

Only ptr[1] points to anything except garbage locations. On three runs of your program, it printed up a $, an 'l', and nothing.

Try this version of your program:

#include<stdio.h>
#include<conio.h>

int fun1 (int a[], int *b);

main()
 {
      char name[15]={'j','o','h','n'};
      char *ptr[3];
              
      ptr[1]=name;
      printf("\n ptr[1] now points to: %s\n", ptr[1]);
      printf("%c", ptr[1][2]);   
      getch();
};

[itsme86]

Only ptr[1] points to anything except garbage locations. On three runs of your program, it printed up a $, an 'l', and nothing.

Try this version of your program:

#include<stdio.h>
#include<conio.h>

int fun1 (int a[], int *b);

main()
 {
      char name[15]={'j','o','h','n'};
      char *ptr[3];
              
      ptr[1]=name;
      printf("\n ptr[1] now points to: %s\n", ptr[1]);
      printf("%c", ptr[1][2]);   
      getch();
};

Yikes. Don't forget to terminate your name string before you try printing it.

Use this line instead:

char name[15] = { 'j', 'o', 'h', 'n', '\0' };

[Elysia]

Ah, another problem joins the fray.
It would be better to do
char name[] = "john";
or
char name[15] = "john";

[itsme86]

Yikes. Don't forget to terminate your name string before you try printing it.

Use this line instead:

char name[15] = { 'j', 'o', 'h', 'n', '\0' };

You know what, actually Adak's solution would have worked since the array size was specified it would fill any non-initialized elements with 0s. My bad.

[iMalc]

You know what, actually Adak's solution would have worked since the array size was specified it would fill any non-initialized elements with 0s. My bad.

No actually it would work because it was only printing a single character (the 'h'), not a string.

[itsme86]

No actually it would work because it was only printing a single character (the 'h'), not a string.

Really? What do you call this line of code?

      printf("\n ptr[1] now points to: %s\n", ptr[1]);