Very stupid question about pointers

Hi, i just want to make sure, Is this correct?

Code:

int f1(char *a)
{
      return f2(&a);
}

int f2(char *a)
{
       *a++;
       return 1:
}

or should be;

int f1(char *a)
{
      return f2(*a);
}

Thank you!!

Think: in f1, a is a char*. Therefore, &a is a char**, and *a is a char. For f2, the parameter a is a char*. Therefore, what should you pass to f2 from f1?

Well did you try them both with a compiler (which would have taken mere seconds)

Both are wrong by the way.

Hmmm .. thats true.. so i would just have to make like this?Yea thats makes sense...

Code:

int f1(char *a)
{
      return f2(a);
}

I tryed to make that like here:

Code:

#include <stdlib.h>
#include <stdio.h>

int f2(char *a);
int f1(char *a);


int main()
{
    char a;
    int b;
        
    a = 100;
    
    b = f1(&a);
       
   printf("%u \n", a);

    
    system("PAUSE"); 
}

int f1(char *a)
{
      return f2(a);
}

int f2(char *a)
{
       *a++;
       return 1;
}

But the output is 100.. whats wrong?

i did try with a++ but with the same output...

Thank you!

Try with (*a)++

It´s a precedence thing.

Also, if you´re using gcc, then use "-W -Wall" as command line options.
IIRC, it would complain that your *a++ was a "unused" side effect.

Thank you!! It worked You helped a lot!! Actually, it did not complain haha. But thank you.

And laserlight made everything more clear to me!!

Cya

-pedantic -O2

Optimisation implies data flow analysis, which might be needed for more advanced unused detection.

Oh, ok i will make use of that!! Thank you!