pointer issue

I'm writting a program that generates a list of random numbers based on predefined parameters and counts the number of positives, negatives, zeros, evens and odds. I had it working fine when it was all in main() but when I broke it up into separate functions it would not display the number of positives etc. correctly.

Here is the code for the part that I believe is giving me trouble:

Code:

int looper(int seed, int upper, int lower, int num, int* pos, int* neg, int* zero,
          int* even, int* odd)
{
   int rnum, teh;      //rnum is random number, teh counts the loops
    
   srand(seed);
   for (teh=0; teh<num; teh++) //loop controles # of randoms
   {
    rnum= (rand()%(upper-lower))+lower;
    if(teh==10 || teh==20 || teh==30 || teh==40 || teh==50)     //new line every 10 loops
     { printf("\n"); }
    printf(" %d", rnum);     //print the random

    if(rnum>0)       //counts positives, neg, zero, even & odds
     { pos++; }
    else if(rnum<0)
     { neg++; }
    else
     { zero++; }

    if((rnum%2)==0)
    { even++; }
    else
    { odd++; }
   }
   printf("\n");
}

That string of if/else statements at the end should be counting the number of evens, odds etc. but all I get for the values is 0 when I compile and run the program. I've looked through the FAQs and my textbook but nothing has clued me in to why it isn't working the way I want.
Thanks in advance for any help.

In this function, what is a variable like "pos"?

int, double char, float, long int, unsigned char?

No - it's a pointer!! And a pointer holds an address value. And you are incrementing THAT ADDRESS value -- which is not what you want.

Try:

Code:

(*pos)++; //yes, you need the parentheses

Thanks, that worked perfectly. I had tried using *pos but didn't use the parentheses.

Yep! Figured as much - we've all been stung by that precedence bee, at some time or other.

And Welcome to the forum, Justinb!