Thread: know the only file name in a directory(Linux)

There is a local diretory alled directory which contins only one file, I want to know the name of the file using c.. here is what I have got from Net:

Code:

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#include<dirent.h>

void getFile (char *);

main()  {
        char s[50];
        getFile(s);
        printf("%s", s);
}
void getFile (char *file)
{
    char dir[100] = "directory/";
    DIR *dp;
    struct dirent *dirp;
    if((dp  = opendir(dir)) == NULL) {
        perror("\nUnable to open directory.");
        exit(0);
    }
    dirp = readdir(dp);
    strcpy(file,dirp->d_name);
    closedir(dp);
}

There is file there in the directory though I get output as:

Code:

.

Is there any other good way to do this? OR what is the problem with this code?
Note: the folder contains only one file.

Thanks all.. but there is no way to know the only file name present in the directory? and what are '.' and '..'?

What I get from you that, I need to check for the names . and .. if the name is not . or .. then that is the name what I am looking for? am I thinking right?

As Salem said

You need to call readdir() in a loop until it returns NULL.

Each call gets you another filename.

The "." is the entry for the current directory. The ".." is the entry for the previous directory.

Jim