delay text in c..

[nyekknyakk]

hi, everyone! i'm currently working on a code that delays a text in c.
the code is something like this:

char text1[SIZE][SIZE] = {"The", "quick", "brown", "fox", "jumps", "over", "the", "lazy", "dog."};

int main() {
	int i, j;
	
	printf("Hi!\n");
	sleep(1000);
	printf("Hello!\n");
	
	for(i=0; i<=9; i++) 
		for(j=0; j<=5; j++) {
			printf("%c", text1[i][j]);
			sleep(100);
			}
	}

the code above shows this output:

The   quick brown fox   jumps over  the   lazy  dog.

what can i do to make the input like this:

The quick brown fox jumps over the lazy dog.

thanks!

[Swarvy]

Instead of:

char text1[SIZE][SIZE] = {"The", "quick", "brown", "fox", "jumps", "over", "the", "lazy", "dog."};

Could you not just have:

char text[] = "The quick brown fox jumps over the lazy dog.";

Then just have one loop instead of two. Go character by character. That should get rid of the spaces between the words too.

Edit: Your for loop will look something like this:

for(i=0; i < strlen(text); i++)
{
       printf("%c", text[i]);
       sleep(100);
}

[Adak]

for(j=0; j<=5; j++) {
			printf("%c", text1[i][j]);
			sleep(100);
			}

Says that you're going to print out 6 letters (char's actually), for each word, regardless of the actual length of the word.

Add some logic (instead of the j<=5), and make the printing stop when j == strlen(text[i]. You'll need to -1 if you want to remove the period from the last word's string.

[nyekknyakk]

thanks very much! that was really helpful..