convert alphabet to integers

hi I'm wanting to convert alphabet to numbers as in a == 1, b == 2. Instead I get asci, so i want to subtract 96. like so:

Code:

#include<stdio.h>
#include<ctype.h>

#define MAXSTRING 100

int main()
{
   char c,name[MAXSTRING];
   int i, sum = 0;

   printf("\nhello!   What is your name? ");
   for (i = 0 ;(c = getchar()) != '\n'; ++i){
      name[i] = c;
      if (isalpha(c))
         //sum += c;
          sum += (c - 96);          
   }
   name[i]='\0';
   printf("\n%s%s%s\n%s",
   "hi ", name, ".",
   "Your name spelt backward is ");
   for(--i ; i  >=0 ; --i)
      putchar(name[i]);
   printf("\n%s%d%s\n\n%s\n",
      "and the letters in your name sum to ", sum, ".",
      "have a nice day\n");
 
   return 0;
}

c - 'a' should do that.
Make sure that c is [a-z] though you could use tolower(c) - 'a'

so i tried

sum += (c - 'a');

Still incorrect answer..Is it something to do with reading a string and omitting end of line character?

if c == 'a', then:
c - 'a' == 0

So if you want 'a' to equal 1, you need to add 1:

Code:

sum += (c - 'a') + 1;

Code:

printf("\n%s%s%s\n%s",
   "hi ", name, ".",
   "Your name spelt backward is ");

printf isn't that difficult to use, the following code would print the same thing

Code:

printf("\nhi %s.\n Your name spelt backward is ", name);

sum += (c - 'a');

'a' - 'a' would equal 0, so you need to add 1 to get the values specified in your original post
try

Code:

sum += c - 'a' + 1;

thanks. got that now