Thread: Need help!

ok so why is it in my program that i cant input a character? it just says that it equals the number 10
insert

Code:

#include <stdio.h>


int main(void)
{
	double T;
	int qty;
	char ch;


	printf("Enter the number of items\n");
	scanf("%d", &qty);

	printf("Enter the price\n");
	scanf("%lf", &T);

	printf("Enter a class\n");
	scanf("%c", &ch);

	printf("%d\n",ch);

	

		return 0;
}

You are printing the character as an integer -- not a character. Use %c in your printf() statement. Also, when you read in a double, use %lf instead of %f.

scanf() leaves a newline char behind, and that is ASCII value of 10, and you're reading it - so it looks like your scanf() for a char is being skipped.

To stop it, put this line, immediately after each scanf() line of code:

getchar();

which will pull the newline char off the keyboard buffer, and leave it "clear".

Edit: To be more precise, scanf() can skip a newline char in the keyboard buffer IF it's looking for a data type that is bigger than a tiny char data type.

But - when scanf() is looking for a char, it can NOT skip a newline char, because that IS just the size of data it is expecting.

So it takes your newline char, says it's just what the doctor ordered, thank you very much, and continues on. Not nice, but true.

Only one good reason why scanf() should not be used for getting user input, later on. It's "fussy" and relies on the data being strictly formatted, and/or you having a very good understanding of just how scanf() works.

Later, look to use fgets(myBuffer, sizeof myBuffer, filePointer);

It is a beauty for user input!