Thread: Using the (int) cast

Hello,

I solved some exercises on the textbook called A First Book of ANSI C by myself and really happy about that. I have a major problem with one exercise. It says i have to use the (int) cast, devise a method to round the values in the variables a and b to the nearest hundredth (penny value) before they are added.

I have no idea what the question means!!! Any advice? I read a different book i brought from Korea to solve it in my own way but I dont know its right or not.

I tried to find solutions for the textbook but cant find it.
Question

Code:

    double a, b, c;
    a = 1.674;
    b = 1.322;
    printf("\n%4.2f",a);
    printf("\n%4.2f",b);
    printf("\n----");
    c = a + b;
    printf("\n%4.2f\n",c);

My code:

Code:

#include<stdio.h>
#include <math.h>
int main()
{
    double a, b, c;
    a = 1.674;
    b = 1.322;
    double  round (double x);
    a = round(a*100)/100;
    b = round(b*100)/100;
    printf("\n%4.2f",a);
    printf("\n%4.2f",b);
    printf("\n----");
    c = a + b;
    printf("\n%4.2f\n",c);
    
    return 0;
}

I got it
Thank you very much!!

Code:

#include<stdio.h>
main()
{
    double a, b, c;
    a = 1.674;
    b = 1.322;
    
    printf("\n%4.2f",a);
    printf("\n%4.2f",b);
    
    a = a * 100;
    b = b * 100;
    printf("\n----");
    
    //round the values in the variables a and b to the nearest hundredth
    a = (int) a;
    b = (int) b;
    
    //add the variables a and b
    c = a + b;
    c = c / 100;
    
    //provide the required result
    printf("\n%4.2f\n",c);
    
    return 0;

}

Originally Posted by Salem

Say you had
double a = 12.3456;

a = a * 100;
becomes 1234.56

a = (int)a;
becomes 1234.00