Beginner stumped..

Program requirements:

Code:

    * Your program should prompt the user to enter the length of the room to be painted.
    * Your program should prompt the user to enter the width of the room to be painted.
    * Your program should prompt the user to enter the height of the room to be painted.
    * Your program should prompt the user to enter the total square footage of windows in the room. After all, you wouldn't expect to paint the windows themselves.
    * Your program should calculate the number of gallons needed to paint the room. Assume that one gallon of paint will cover 200 square feet of wall.
    * Your program should print a message indicating how many gallons of paint will be needed to paint the room.

We were given a program to write outside of class for extra. I am stuck though..

This is what I have, not sure where to go though...

Code:

#include <stdio.h>
	main()
{	


	Paint values = 1 gallon of paint covers 200 square/feet.

	        
	printf("input room dimensions\n");
	printf("length? ");
	scanf("%f", &length);
	printf("width? ");
	scanf("%f", &width);
	printf("height ?");
	scanf("%f", &height");

	printf("input total square/feet of windows in room\n");
	printf("sqaure_feet? ");
	scanf("%f", &square_feet);

	wall_area = 2*height*(length+width)-(window_area + door_area);
	gallons = (wall_area/window_area) + 0.999 ;
	printf("number of gallons needed to paint room = %d\n", gallons);

}

Any help? This is my first programming class to take, so it is a bit foreign to me..

Originally Posted by kiorei

Program requirements:

Code:

    * Your program should prompt the user to enter the length of the room to be painted.
    * Your program should prompt the user to enter the width of the room to be painted.
    * Your program should prompt the user to enter the height of the room to be painted.
    * Your program should prompt the user to enter the total square footage of windows in the room. After all, you wouldn't expect to paint the windows themselves.
    * Your program should calculate the number of gallons needed to paint the room. Assume that one gallon of paint will cover 200 square feet of wall.
    * Your program should print a message indicating how many gallons of paint will be needed to paint the room.

We were given a program to write outside of class for extra. I am stuck though..

This is what I have, not sure where to go though...

Code:

#include <stdio.h>
	main()
{	


	Paint values = 1 gallon of paint covers 200 square/feet.

	        
	printf("input room dimensions\n");
	printf("length? ");
	scanf("%f", &length);
	printf("width? ");
	scanf("%f", &width);
	printf("height ?");
	scanf("%f", &height");

	printf("input total square/feet of windows in room\n");
	printf("sqaure_feet? ");
	scanf("%f", &square_feet);

	wall_area = 2*height*(length+width)-(window_area + door_area);
	gallons = (wall_area/window_area) + 0.999 ;
	printf("number of gallons needed to paint room = %d\n", gallons);

}

Any help? This is my first programming class to take, so it is a bit foreign to me..

First make your main return int:

Code:

int main()
{
       code here

     return 0;

}

Second, you are using float variables (length, height, etc.) without any
declarations. I'm assuming you know how to do that.

Edit:

Code:

Paint values = 1 gallon of paint covers 200 square/feet.

<--- what is that supposed to do?

Edit#2:

:Paint values = 1 gallon of paint covers 200 square/feet.

With the statement above, I've come to the conclusion that you probably don't know how to declare variables yet. Check out the link below.


http://en.wikipedia.org/wiki/C_varia...d_declarations

Ah. you are right. I am trying to follow along with the book Through C to C++: a complete programming course with what I am doing. Doesn't look like that is helping too much it seems.

Thanks for the link and for replying.

Edit.

Ok, I think this is better. It looks closer to what the book is using..

Code:

#include <stdio.h>

	void main(void)
{
	const	float	paint_cover = 200.0;

	
	float	length, width, height;
	float	wall_area;
	int	gallons;


	printf("input room dimension\n");
	printf("length? ");
	scanf("%f", &length);
	printf("width? ");
	scanf("%f", &width);
	printf("height? ");
	scanf("%f", &height);

	wall_area = 2*height*(length + width)- (window_area)
	gallons = (wall_area / paint_cover) + 0.999;

	printf("number of gallons needed to paint room = %d\n", gallons);

}

The question I have is how do I declare window_area a unknown, as it is left up to the user...

or is this completely wrong...