Please halp, the code will not run...simple division.

This is a discussion on Please halp, the code will not run...simple division. within the C Programming forums, part of the General Programming Boards category; Not sure what I'm doing wrong. Please help me debug this. Using C. Ch compiler. Code: #include <stdio.h> /* standard ...

  1. #1
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    Please halp, the code will not run...simple division.

    Not sure what I'm doing wrong. Please help me debug this. Using C. Ch compiler.

    Code:
    #include <stdio.h>			/* standard IO library routines, like printf, scanf */
    
    
    
    
    int main(void)
    {
        
        char length_unit[30];
        float conversion_factor, equal_distance, newmiles;
        
        printf("Enter the name of the length unit you want to convert to> ");
        scanf("%s", &length_unit);
        printf("You entered: %s\n", length_unit);
        printf("Enter the conversion factor> ");
        scanf("%f", &conversion_factor);
        printf("You entered a converison factor of %.4f%s/mile\n", conversion_factor, length_unit);
        printf("Enter the distance in miles > ");
        scanf("%f", &newmiles);
        printf("You entered: %.4f miles \n", newmiles);
        
        equal_distance = coversion_factor / newmiles;
        
        printf("The equivalent distance is %f\n", equal_distance);
        
        return 0;		
    }

  2. #2
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    the division part halts the code

  3. #3
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    You forgot the info on the unit you are converting FROM. Aha!

  4. #4
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    hi! thank you for responding to my post. Can you please be a little specific?

  5. #5
    Registered User Char*Pntr's Avatar
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    Quote Originally Posted by team23 View Post
    Not sure what I'm doing wrong. Please help me debug this. Using C. Ch compiler.

    Code:
    #include <stdio.h>			/* standard IO library routines, like printf, scanf */
    
    
    
    
    int main(void)
    {
        
        char length_unit[30];
        float conversion_factor, equal_distance, newmiles;
        
        printf("Enter the name of the length unit you want to convert to> ");
        scanf("%s", &length_unit);
        printf("You entered: %s\n", length_unit);
        printf("Enter the conversion factor> ");
        scanf("%f", &conversion_factor);
        printf("You entered a converison factor of %.4f%s/mile\n", conversion_factor, length_unit);
        printf("Enter the distance in miles > ");
        scanf("%f", &newmiles);
        printf("You entered: %.4f miles \n", newmiles);
        
        equal_distance = coversion_factor / newmiles;
        
        printf("The equivalent distance is %f\n", equal_distance);
        
        return 0;		
    }
    This thread looks familiar... see above in bold red.

  6. #6
    a_capitalist_story
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    Your code doesn't even compile, because as mentioned in your duplicate thread, "coversion_factor" is not the same as "conversion_factor".

  7. #7
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    Doh!! Thank you. I was working on this really late last night, i must have missed the obvious.

  8. #8
    C++まいる!Cをこわせ! Elysia's Avatar
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    SourceForge.net: Scanf woes - cpwiki
    Your program is a ticking time bomb. Take some time to read the article on why scanf is not recommended for reading strings.
    Quote Originally Posted by Adak View Post
    io.h certainly IS included in some modern compilers. It is no longer part of the standard for C, but it is nevertheless, included in the very latest Pelles C versions.
    Quote Originally Posted by Salem View Post
    You mean it's included as a crutch to help ancient programmers limp along without them having to relearn too much.

    Outside of your DOS world, your header file is meaningless.

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