I think must use pointers in this prog but i dunno where to start..
"you are given a time in seconds. You are required to write a full program consists of a function
to convert it to hours, minutes and seconds. Your function should require three address parameters
to return the values."
It probably means something like this:
You want to convert the seconds to hours, minutes and seconds. So 3601 secs would be 1h 0m 1s. So you have 3input and you want to give 1 output.
In C there are two ways to actually store the outputs with a function. Those are
considering that you want to save a value of type. You will save that value inside a variable names output.Code://1st int fun() { int output; ... output = value; ... return output; } //Call like int output; output = fun(); //2nd void fun(int* output) { ... *output = value; ... } //Call like int output; fun(&output);
You will use the second method. To hint it should be like
where in1, in2, in3 are you input and out your output, of course you would need to put types on them.Code:void fun(in1, in2, in3, out);
If you need any clarifications just keep posting 'till you figure it out.
EDIT: The & symbol means that you get the address. You could write the second like this to be more clear
Code:int output; int* outPtr; outPtr = &output; //point to variable fun(outPtr); //the variable output has the value you want, since it where outPtr points
Last edited by C_ntua; 08-12-2010 at 09:24 PM.
Actually, the question only allows 3 inputs.Code:void fun(in1, in2, in3, out);
So something like this:
Code:void fun(int * secs, int * mins, int * hrs);
The question asks for three parameters to return the result. So you'd have to a 4th to pass the actual inputted time to the user probably.
Originally Posted by Adak
Example usage of your function will be something like:
Post the code if you have any problem.Code:int hour,sec,min; sec = 1000; foo(&hour,&min,&sec); // name is just eg ONLY! printf("Hour = %d, min = %d, sec = %d\n",hour,min,sec);
I honestly think this is better, Separate input from output.
Code:int hour,sec,min; int total_time = 1000; foo(total_time, &hour,&min,&sec); // name is just eg ONLY! printf("Hour = %d, min = %d, sec = %d\n",hour,min,sec);
I'd rather use struct.
Code:typedef struct Time { int hour; int min; int sec; } Time; void foo(Time *t) { ... } Time t = { .sec = 1000 }; foo(&t); print_time(&t);
I don't think there are enough variables to bother with that.
Anyhow, it violates the requirements which is 3 variables out.
