o/p:Code:int main()
{
char a[]={1,2,3,4,5};
char *cp;
int *ip;
clrscr();
cp = a;
ip=(int*)cp;
printf("%d \n",*(cp+2));
printf("%d \n",*(ip+1));
}
3
1027
The o/p value 1027 is because as pointer ip is a pointer to an int(if size of int is 2 bytes) then it will print the value 0x0304.
what is the output of ( printf("%d \n",*(ip+1)) if it is little endian and what is the output if it is big endian machine?
