when I try this code:
can anyone explain this odd behavior?Code:void main() { int l; char a[3]={'d','b','c'}; l=strlen(a); printf("%d",l); } I am getting o/p as 4. void main() { int l; char a[4]={'d','b','c'}; l=strlen(a); printf("%d",l); } o/p is 3.
I am using turboc3 in winxp
The weird thing is that you are using strlen on an array of char that does not have a null character, and thus is not considered a string with respect to strlen.
Look up a C++ Reference and learn How To Ask Questions The Smart WayOriginally Posted by Bjarne Stroustrup (2000-10-14)
Turbo C is very old.
Why don't you use something like visual C++ or gcc ?
...And changing void main to int main? SourceForge.net: Revision history of "Void main" - cpwiki
Or rather you should get rid of Turbo C: SourceForge.net: Turbo C - cpwiki
And get a better IDE/compiler: SourceForge.net: Integrated Development Environment - cpwiki
Last edited by Elysia; 07-18-2010 at 09:05 AM.
You need to add a '\0' to be considered a string.
An easier way to do this is by initializing like this,
Code:char a[] = "abc"; or char a[4] = "abc";
If you don't intend to leave space for the null terminator, then you probably intend to use sizeof instead of strlen.
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