struct struct struct problem....please....help!!!

I believe i am wrong in the two red points...is it right? also whats the problem?
thanks in advance....

Code:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

struct Info{
	char name[81];  
	int phone;    
	char street[81];
	char email[81];
};


void print(struct Info info.name, struct Info info.phone, struct Info info.street, struct Info info.email){

			printf("Name: %s\n", info.name);
			printf("Phone Number: %d\n", info.phone);
			printf("Street address: %s\n", info.street);
			printf("E-mail: %s\n", info.email);
}


int main(void){
	FILE *infile;
	struct Info info;
	
		infile = fopen("file.txt","r");

		if(infile==NULL){
			printf("Error :(\n");
			exit(1);
		}
	
		while(fscanf(infile,"%s %d %s %s", info.name, &info.phone, info.street, info.email)!=EOF){
			print(info.name, info.phone, info.street, info.email);	
		}
	
	return 0;
}

Try something simpler:

Code:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

struct Info{
	char name[81];  
	int phone;    
	char street[81];
	char email[81];
};


void print(struct Info info){

			printf("Name: %s\n", info.name);
			printf("Phone Number: %d\n", info.phone);
			printf("Street address: %s\n", info.street);
			printf("E-mail: %s\n", info.email);
}


int main(void){
	FILE *infile;
	struct Info info = {"Buzz Lightyear", 12345, "Infinity Way", "bl@tomorrow.com" };
	
		/*infile = fopen("file.txt","r");

		if(infile==NULL){
			printf("Error :(\n");
			exit(1);
		}
	
		while(fscanf(infile,"%s %d %s %s", info.name, &info.phone, info.street, info.email)!=EOF){
    */
			print(info);	
		//}
	
	return 0;
}

The way you're trying to do things more or less defeats the purpose of a struct. Why would you bother putting it all together if you always had to deal with the struct members individually? It'd be useful as a sort of namespace, but that's about it.

Thankfully, C's not like that:

Code:

#include <stdio.h>
struct info
{
  int a, b, c;
};
void f(struct info info)
{
  printf("%d %d %d\n", info.a, info.b, info.c);
}
int main(void)
{
  struct info info = { 10, 20, 30 };
  f(info);
  return 0;
}

You can just pass a struct around; you needn't try to pass each individual member.

You'll probably want to pass a pointer around instead of the struct itself (this becomes more relevant the larger your struct gets):

Code:

#include <stdio.h>
struct info
{
  int a, b, c;
};
void f(struct info *info)
{
  printf("%d %d %d\n", info->a, info->b, info->c);
}
int main(void)
{
  struct info info = { 10, 20, 30 };
  f(&info);
}

x->y is the same as (*x).y; that is, dereference a struct (or union) pointer and then access a member.

void print(struct Info info.name, struct Info info.phone, struct Info info.street, struct Info info.email){


You're passing in info.name, which is a char array
it should be

Code:

void print(char[] name, .......){
   printf(name......);
   ....
   ...
}

you're don't understand how to pass parameters? it's the same as in Java or any other language

Originally Posted by dayalsoap

void print(struct Info info.name, struct Info info.phone, struct Info info.street, struct Info info.email){


You're passing in info.name, which is a char array
it should be

Code:

void print(char[] name, .......){
   printf(name......);
   ....
   ...
}

you're don't understand how to pass parameters? it's the same as in Java or any other language

you are right. i don' t...C is my first language and that is why i make these mistakes...i don' t know if C is a bit difficult but i don' t know another language yet!

Don't feel bad passing function parameters can be a bit tricky. I am new as well and have to really think carefully what is being passed and how. I found this link to be helpful

Passing Arguments to Function

Also there is a really good set of videos for beginning C that goes through parameter passing functions and structs (this is where I learned if from) you can find it here:

CSE 142 TVI - Lectures, Autumn 2000

If you use the url the slides are synced to the video lecture.

I hope this will help you out some.