Thread: Using string functions

Hello
i was wondering if someone can help me code a little bit, I understand how some of it works, and ill show what i have, I just dont know how to put this work in a loop. Thanks
If in starts with "abc32fe5v" it should end up with only alpha characters so Out should = "abcfev"

alpha - character array stores the eniter alphabet

1. strspn("abc32fe5v",Alpha) gives 3
2. strcpy the first 3 chars of "abc12de6x" to Out
3. strcspn("32fe5v",Alpha) gives 2, so skip over the net 2 chars of "21fe5v"

1. strspn("fe5v",Alpha) gives 2
2. strcpy the first 2 chars of "fe5v" to Out
3. strcspn("5v",Alpha) gives 1 so skip over 1 chars of "5v"

1. strspn("v",Alpha) gives 1
2. strcpy the first 1 char of "v" to Out
3. strcspn("",Alpha) gives 0 so skip over 0 chars of ""
loop ends because In is finished

thanks, I know it would be eaiser however, it requires the use of these functions

Here's one way.

Code:

#include <stdlib.h>
#include <stdio.h>
#include <string.h>
//alpha - character array stores the eniter alphabet
char *Alpha = "abcdefghijklmnopqrstuvwxyz";
int main(void)
{
char *original = "abc32fe5v";
char Out[80] = "";
size_t alpha_count;
char *p;

p = original;
while (*p != '\0')
{
   alpha_count = strspn(p,Alpha);
   printf("alpha_count:%d\n",alpha_count);
   strncat(Out,p,alpha_count);
   p += alpha_count;
   printf("p:%s\n",p);
   p += strcspn(p,Alpha);
   printf("p:%s\n",p);
   getchar();
}
printf("Out:%s\n",Out);
return 0;
}

thank you very much for your help, it works like a charm.....