We know , in a union memory is allocated for the element having the maximum size.
So will the following initialization work:
Code:union b { char ch[2]; int i; }; int main() { union b z2={0,2}; return 0; }
We know , in a union memory is allocated for the element having the maximum size.
So will the following initialization work:
Code:union b { char ch[2]; int i; }; int main() { union b z2={0,2}; return 0; }
No, but you can use something like this:
EDIT: It seems to be working, had a typo.Code:union b z2 = { .ch = {0, 2} }
Last edited by Memloop; 06-13-2010 at 07:34 PM.
@Memloop
What does the above code do exactly?Code:union b z2 = { .ch = {0, 2} }
Does it initialize ch to 0 and i to 2??
Yes.
No it doesn't. It initialises z2.ch[0] to 0 (zero) and z2.ch[1] to 2.
I misread it as "initialize ch to 0 and 2".
> So will the following initialization work:
It should do - did you try it?
I believe memloop's answer requires a C99 compiler to work.
Prior to C99, you could only initialise the first named member of the union.
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