'Makes pointer from integer without a cast'

New to C. I do realize that there are threads about this problem everywhere, but I've searched through at least half of them and haven't yet found one that properly applied to this situation.

I get the warning "passing arg 1 of `strcpy' makes pointer from integer without a cast". I know what this means but I don't know how to fix it in this case.

Code:

/* Declare variables */
char command[50][10]; /* Array to store commands into */
int i, j, k, l, m = 0; /* Counter variables for command storage */

int main( void )
{

    /* Declare variables */
    FILE *file; /* File used for reading */
    char *tokenPtr; /* Current word being read */
    char fileName[6]; /* File name */
    
    /* Arrays */
    char line[80][50]; /* Array to store line in the file */

    /* Iterate through the lines array */
    for( j = 0; j < i; j++ ) {

        /* Tokenize line with a space, new line, and tab delimiter */
        tokenPtr = strtok( line[j], " \n\t" );
        /* Convert tokenized into upper case */
        *tokenPtr = toupper( *tokenPtr );

        /* As long as there are still more words to be read */
        while( tokenPtr != NULL ) {

            /* Copy the line's words into the command array */
            strcpy( command[j][k], tokenPtr );
            /* Increment counter for second index */
            k++;

            /* Get next token */
            tokenPtr = strtok( NULL, " \n\t" );

        }
        
        k = 0;
    }

}

Next part, I want to compare a value to NULL. I would just like to ask if this would be the same thing as comparing to zero.

Code:

   /* Determine error type and print out corresponding error message */
    if( command[m][1] < 0 ) {
        printf( "\nError: Parameter cannot have a value under 1.", command[m][0] );
    } else if( command[m][1] == 0 ) {
        printf( "\nError: Command %s takes in an int parameter.", command[m][0] );
    }

Thanks for any help!

command[j][k] is of type char and holds a single char, so you can't just copy an entire string into it.

> Next part, I want to compare a value to NULL. I would just like to ask if this would be the same thing as comparing to zero.

It's better to use NULL if you're comparing pointers. It's more accepted to use 0 instead of NULL when programming in C++ though.

Not to mention:

Code:

int i, j, k, l, m = 0; /* Counter variables for command storage */

int main( void )
{

    /* Declare variables */
    FILE *file; /* File used for reading */
    char *tokenPtr; /* Current word being read */
    char fileName[6]; /* File name */
    
    /* Arrays */
    char line[80][50]; /* Array to store line in the file */

    /* Iterate through the lines array */
    for( j = 0; j < i; j++ ) {
...

You're using 'i' without initialising it.

Originally Posted by Memloop

...It's more accepted to use 0 instead of NULL when programming in C++ though.

Absolutely not. Don't say such things.
This is trend that will be phased out.

> Absolutely not. Don't say such things.

What's not right about it? Almost every single C program uses NULL when comparing pointer values, but there are many C++ programs (most that I've seen anyway) that compare against 0 instead of NULL since Stroustrup recommends it.

I only see that he prefers to avoid macros. But as I said, while legal, it's a dying trend. In C++0x, it's nullptr, and NULL and 0 will be kept only for backwards compatibility.
Besides that, there is a NULL pointer, but there isn't a 0 pointer.
Similarly, there isn't a NULL value, but there is a value 0.
So to sum it up: don't use 0. Use NULL. Or better yet, nullptr.