concatonate memory buffers

[it99]

I have two things I'd like to concatenate together

uint 8*buffer; // this is just a data buffer

struct *aHeaderStruct; // some header structure

I'd like to prepend the header struct in front of the data buffer.

What is the best way to do that?

Thanks

[Kennedy]

memcpy() would work into a third buffer, however, the _BEST_ way would be to make another structure that contains both of the items you want.

[Epy]

Can I ask why you would want to do such a thing?

[MK27]

I'd like to prepend the header struct in front of the data buffer.

Just do it then.

I think you need to provide some more context WRT where the "prepending" will occur. Like you want another struct? You want to transmit this thru a socket? You want to write it to a file? What?

[it99]

Just do it then.

I think you need to provide some more context WRT where the "prepending" will occur. Like you want another struct? You want to transmit this thru a socket? You want to write it to a file? What?

I am trying to send these through a socket. I have a structure I want to prepend to a buffer of data. So I really just want it as a buffer of data that I can send through socket.

[MK27]

uint_8 *buffer; // this is just a data buffer
struct somestruct *aHeaderStruct; // some header structure
int sock; // your socket
send (sock, aHeaderStruct, sizeof(struct somestruct),0);
send (sock, buffer, sizeof(uint_8),0);

The sizes there may not be inappropriate, but there is nothing special you need to do. You just send the data.

It's a good idea to use the return value of send with sockets in a loop to make sure all the data has been sent/recieved, eg:

unsigned char *data;
int sz = // the data length
int total = 0, sent;
while (total < sz) {
    sent = send(sock,&data[total],sz-total,0);
    total += sent;
}