Can anyone help me with these errors?

[nullifyed]

#include <stdio.h>
#include <stdlib.h>

struct Files{
	char name[40];
	int years;
	int age;
};


void f_age(struct Files data, int num){
	int i;
	
	for(i=0; i<num; i++){
		printf("Please type your age:\n");
		scanf("%d", &data[i].age);
	}	

}


int main(void){
	int i, number;
	struct Files *data;
	
	printf("Please type a number for the variable number:\n");
	scanf("%d", &number);
	
	data=(struct Files *)malloc(number*sizeof(struct Files));
	
	f_age(data, number);
	
//	for(i=0; i<number; i++){
//		printf("Please type your age:\n");
//		scanf("%d", &data[i].age);
//	}	
	
	for(i=0; i<number; i++){
		printf("Age[%d]: %d\n", i, data[i].age);
	}
	
	return 0;
}

output: vasileios@vasileios-desktop:~/desktop$ gcc askisi1.c

askisi1.c: In function ‘f_age’:
askisi1.c:17: error: subscripted value is neither array nor pointer
askisi1.c: In function ‘main’:
askisi1.c:32: error: incompatible type for argument 1 of ‘f_age’
askisi1.c:12: note: expected ‘struct Files’ but argument is of type ‘struct Files *’

I am not so good in structs...and...working with fuctions but i still try to learn...there are some errors when i call the f_age in main and also when i initialize the variables...if anyone khows what's wrong please tell me...thanks...

[Bayint Naung]

void f_age(struct Files data[ ] , int num){

[claudiu]

In function f_age you should be passing a pointer since you are changing the argument's fields in that function. You are doing that correctly in main() but your f_age header is incorrect. Add the * symbol before the data argument to make it a pointer. Also, change the . (dot) to -> arrow when accessing the members in the scanf statement.

Alternatively, if you want to use arrays you can make the argument [].

Also, please note that there is no need to cast malloc unless you are compiling in C++.

[nullifyed]

Thank you very muck...something else...do you know how can i change my profil name?

[Bayint Naung]

Alternatively, if you want to use arrays you can make the argument [].

Can you explain what it is ???

[nullifyed]

If i am correct, [ ] means array! There are two ways to show that sth is an array:
1) A[ ];
2) *A;

However, i don' t understand the "->" ! Having only the " *A " is not enough? Can sb explain this?

[claudiu]

If the variable for which you are accessing members is a pointer, -> must be used. If it is not, . must be used.

example:

struct something{
   int x;
};

struct something *my_ptr_to_struct = malloc(sizeof(struct something));
my_ptr_to_struct->x = 3;

struct something my_struct;
my_struct.x = 3;

[Bayint Naung]

p->a is just syntactic sugar for (*p).a (note you need parenthesis because operator precedence)

Food for thought.