Function problem (recursion)

[chaklader]

I want to calculate the formula : 1+2+3+4+............+n = n (n+1)/2. anyone will help me to find the error of the program? it just show an error result ........

// Function (RECURSION)

       # include<stdio.h>
       
       int funct1(int n);

	   void main()

	   {
		 int n,t;
	     printf("Enter the value until which you want to sum up\n");
		 scanf("%n", &n);

		 t= funct1(n);

		 printf("  summation= %d", t );
	   
	   }


	   int funct1(int n)

	   {
	    
		   if (n>0)

			return (n+ funct1(n-1));

	   }

[DeadPlanet]

According to the scanf docs there's no such specifier as "%n". There are different ones to use depending on exactly what you need, the documentation describes them all.

scanf - C++ Reference

There's no 'bottom case' (can't remember what it's called) for your recursive function. You need to specify something to return for when it does get to zero.

[karthigayan]

Every thing is ok.other than the '%n' in the scanf .You have to use '%d' is it .

  # include<stdio.h>

       int funct1(int n);

          int main()
           {
                 int n,t;
                 printf("Enter the value until which you want to sum up\n");
                 scanf("%d", &n);

                 t= funct1(n);

                 printf("  summation= %d", t );

           }


           int funct1(int n)

           {

                   if (n>0)

                        return (n+ funct1(n-1));

           }

[Bayint Naung]

You forget base case.

int funct1(int n)
{
  if(n > 0)
   return n + funct1(n-1);
 return 0;
}

Btw, do you enable compiler warning?

[chaklader]

DeadPlanet, karthigayan and Bayint Naung @ its working now . thank you all .