having trouble solving a program

Hi all, i was having trouble solving this question:

Write a C program that displays all numbers from 1 to Y,which are divisible by a given number X, Where the user enters the values of X and Y.

ex: if the entered values of X and Y are 3 and 30 respectively ,the program will produce the following output:

" Numbers from 1 to 30 divisible by 3 are : 3 6 9 12 15 18 21 24 27 30"


here is my work so far , can anyone help me with the rest of the program or correct the loop for me ?

Code:

---

#include <stdio.h>
#include <conio.h>
main()
{
int X,Y,i;
printf("Please Enter value of  X,Y");
scanf("%d%d",&X,&Y);
for(i=1;i<=Y;i++)
printf("Numbers from 1 to %d divisible by 3 are : %d",Y,i);
getch();
}

---

Well, you don't have the logic down yet. You are just printing out all the numbers between 1 and y.

You need to test if they are divisible by x before you print them.

So just test if i is divisible by x. If it is print it . Think about the definition of divisibility in order to deduce what your testing condition should be.

how do i test if a no. divided a no. gives an int not a float value ? do i use the % ? help plz

Code:

---

#include <stdio.h>
#include <conio.h>
main()
{
int X,Y,i;
printf("Please Enter value of  X,Y");
scanf("%d%d",&X,&Y);
while(i%X==0)
for(i=1;i<=Y;i++)
printf("Numbers from 1 to %d divisible by 3 are : %d",Y,i);
getch();
}

---

but still not printing what i need , any adjustments please ?

Quote:

---

Originally Posted by everyone0

how do i test if a no. divided a no. gives an int not a float value ? do i use the % ? help plz

---

Yes you use %. A number is divisible by another number if the remainder of the division of that number by the second number is 0. Test for that in an if statement inside your for loop and you are done.

i did test for that , thanks but can u tell me how to give this exact printout ? " Numbers from 1 to 30 divisible by 3 are : 3 6 9 12 15 18 21 24 27 30" cause my printf dont do it

post your code with your new test condition included.

did that already lol

If the numbers are "divisible by N", why not just make the loop increment by that amount?

You're doing it wrong. You don't use a loop with % foo == 0, you use that as a check:

Code:

---

for( x = 0; x < 100; x++ )
{
    if( this % that == thisotherthing )
        printf( "%d %% %d has %d has a remainder\n", this, that thisotherthing );
}

---

You aren't actually thinking about what you are doing, you're just throwing lines of code in and hoping it does what you want.


Quzah.