syntax error before '?' token

This is a discussion on syntax error before '?' token within the C Programming forums, part of the General Programming Boards category; Code: #include <stdio.h> #include <stdlib.h> struct Employee{ int age; int a; }; int main(void){ int i, rows; struct Employee *Array; ...

  1. #1
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    syntax error before '?' token

    Code:
    #include <stdio.h>
    #include <stdlib.h>
    
    struct Employee{
           int age;
           int a;
    };
    
    int main(void){
        int i, rows;
        struct Employee *Array;
      
               printf("Please type how big the array you want to be:\n");
               scanf("%d", &rows);
               
               Array = (struct Employee *)malloc(rows*sizeof(struct Employee));
      
               /* Testing if everything went well */
               
               for(i=0; i<rows; i++){
                        Array[i] = ?;
                        printf("A[%d] = %d\n", i, Array[i]);
               }
               
      system("PAUSE");
      return 0;
    }
    Insteed of ? what can i put so as to compile right and run?

  2. #2
    {Jaxom,Imriel,Liam}'s Dad Kennedy's Avatar
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    Data.

    EDIT: ::yawns:: okay, I guess I'll expand this a bit. What do you think an array is? How do you "print" a struct? Is this array a %d in the printf? The operator ? is called a tertiary and is used like (<comparison> ? <response if true> : <response if false>).
    Last edited by Kennedy; 05-25-2010 at 08:44 PM.

  3. #3
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    as? numbers? characters? can you give me an example?

  4. #4
    Captain Crash brewbuck's Avatar
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    I've got this program...

    Code:
    int main()
    {
        ?;
    }
    What should I put in there?
    Code:
    //try
    //{
    	if (a) do { f( b); } while(1);
    	else   do { f(!b); } while(1);
    //}

  5. #5
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    whatever you want....some commands...there is no "special" answer...right?

  6. #6
    Registered User claudiu's Avatar
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    What makes you think that you can print a struct using %d?

    A better question: Even if that worked, what would you expect the program to output?
    1. Get rid of gets(). Never ever ever use it again. Replace it with fgets() and use that instead.
    2. Get rid of void main and replace it with int main(void) and return 0 at the end of the function.
    3. Get rid of conio.h and other antiquated DOS crap headers.
    4. Don't cast the return value of malloc, even if you always always always make sure that stdlib.h is included.

  7. #7
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    Code:
        for(i=0; i<rows; i++){
                      struct Employee dummy = { 0 , 0 };
                        Array[i] = dummy;             /* struct assignment */                    
               }
    Code:
         // using C99
                     for(i=0; i<rows; i++){
                        Array[i] = (struct Employee) { .age = 0, a. = 0 };  
                     }

  8. #8
    Guest Sebastiani's Avatar
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    Code:
         // using C99
                     for(i=0; i<rows; i++){
                        Array[i] = (struct Employee) { .age = 0, a. = 0 };  
                     }
    I'm still bitter that they left that facility out of the C++ standard. Arghh!
    Code:
    #include <cmath>
    #include <complex>
    bool euler_flip(bool value)
    {
        return std::pow
        (
            std::complex<float>(std::exp(1.0)), 
            std::complex<float>(0, 1) 
            * std::complex<float>(std::atan(1.0)
            *(1 << (value + 2)))
        ).real() < 0;
    }

  9. #9
    Registered User TheBigH's Avatar
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    I think maybe you haven't got a good handle on how structures work. What youve set up is an array of employees, each with an age and an "a", whatever that is. You'd access the age of employee number 15 as Array[15].age. Look at the modification I made to your code and see if you can follow how it works.

    Code:
    #include <stdio.h>
    #include <stdlib.h>
    
    struct Employee{
           int age;
           int a;
    };
    
    int main(void){
        int i, rows;
        struct Employee *Array;
      
               printf("Please type how big the array you want to be:\n");
               scanf("%d", &rows);
               
               Array = (struct Employee *)malloc(rows*sizeof(struct Employee));
      
               /* Testing if everything went well */
               
               for(i=0; i<rows; i++){
                        Array[i].age = i;
                        Array[i].a   = 100+i;
                        printf("A[%d] age = %d\n", i, Array[i].age);
                        printf("A[%d] a   = %d\n", i, Array[i].a);
               }
               
      system("PAUSE");
      return 0;
    }

    H.

  10. #10
    Registered User
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    Thank you very much "THEBigH". This was what i was looking for! I understood your example, i just don' t know structs yet...i am on a learning phase...

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