counting by fives

how do i make my program count by fives or tens

Code:

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#include <stdio.h>

main()

{

int x;

for ( x = 100; x > 1; x-- )
        printf("\n%d\n", x);
}

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Make the change of x in the loop a multiple of five (or ten). Alternately, print x*5 (or x*10).

Your x changes by a factor of five, duh.

Replace x-- with x = x+5. And for tens, use x = x+10.

Quote:

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Originally Posted by Babkockdood

Replace x-- with x = x+5. And for tens, use x = x+10.

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This suggestion echos the spirit of the earlier posts, but note that if you actually implement it, you will end up with an infinite loop.

Just decrement by 5.

How about this?

Code:

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for ( x = 100; x > 1; x--, x--, x--, x--, x--)
        printf("\n%d\n", x);

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Code:

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X-=5

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Oh for God's sakes I think the OP got it already.