Thread: String problem

How can I input into one %s.
in this manner,

scanf("%s",&x);

a string with spaces (and still maintains the spaces);

The Day of the Dragon
Young Gun of Of Love
Mouse of Gondar

so when I compare it, it will still be in spaces.

here is one way of doing it

Code:

char tony[10];   // the last space of the array is  /0
    
    printf("enter name");  
    gets(tony);  // gets  function  will take the white spaces
    
    printf("\nname is %s",tony); // this is the proof that it work

I would prefer a much bigger char array size - "The Day of the Dragon" and other titles will never fit into an array of 10 char's.

Code:

fgets(arrayName, sizeof(arrayName), stdin);

may seem overkill, but even with removing the newline hassle:

Code:

if(arrayName[strlen(arrayName)- 1] == '\n')
   arrayName[strlen(arrayName)- 1] = '\0';

it's still a much safer input method.

you overkill it men. you can change the array size to a larger number if you want

Originally Posted by mouse666666

here is one way of doing it

Code:

char tony[10];   // the last space of the array is  /0
    
    printf("enter name");  
    gets(tony);  // gets  function  will take the white spaces
    
    printf("\nname is %s",tony); // this is the proof that it work

I tried your code, and it works, thanks, but I am now having a problem with my code.

Code:

{
	
	char n = '0'; 
	int x = 0;
	int loop = 0;
	int count = 0;
	char trial[50];
	
	system("cls");
	printf("\n *** Search for an Item ***\n\n");
	printf(" 1. Book\n");
	printf(" 2. DVD\n\n > ");
	n = getch();

	if (n=='1')
	{
		printf("\nDo you want to search by:\n");
		printf("[1]title\n");
		printf("[2]Author\n");
		printf("[3]Subject\n");
		printf("[4]Call Number\n");
		scanf("%d",&x);

		switch(x)
		{
		case 1:	printf("Please input the title\n");
				gets(trial);

				for(loop = 0; loop < 100; loop++)
				{
					if(strcmp(trial,ptr->title) != 0)
					{
						printf("hehe\n");
						ptr++;
						count = 1;
						continue;
					}
					if(strcmp(trial,ptr->title) == 0)
					{
						count = 0;
						printf("XXXXXXXXXXXXXXX");
						break;
					}
				}
				break;
		}	
	}
}

on my switch case, every time I put one, it just passes through my code. I got no chance to type my search. any idea?

Originally Posted by mouse666666

there should not be a quotation if(n=='1')
it should be if(n==1)

n is a single char.

Originally Posted by mouse666666

u are comparing n to and integer; by the way what school do you go to because i did this when i was in university

uh...
char n = '0';

I didn't write
int n = 1;

didnt see that

Originally Posted by mouse666666

didnt see that

can't find my error in the for-loop. I don't think I have one.