Silly problem

Code:

#include <stdio.h>
#include <stdlib.h>

struct test_struct
{
  double **array;
  int test;
};

int main()
{
  struct test_struct kyle;

  kyle.test = 18;
  printf("test = %d\n",kyle.test);
  kyle.array = (double **) malloc(5*sizeof(double *));
  if (kyle.array == NULL)
  {
    printf("fail");
  }
  int i = 0;
  for (i = 0; i < 5; i++)
  {
    kyle.array[i] = (double *) malloc(10*sizeof(double));
    if ( kyle.array[i] == NULL)
    {
      printf("fail2");
    }
  }
  
  int j = 0;
  for (i = 0; i < 5; i++)
  {
    for(j = 0; j < 10; j++)
    {
      kyle.array[i][j]=i*j;
    }
  }
  
  for (i = 0; i < 5; i++)
  {
    for(j = 0; j < 10; j++)
    {
      printf("%d\t",(int) kyle.array[i][j]);
    }
    printf("\n");
  }
  
  for (i = 0; i < 5; i++)
  {
    free(kyle.array[i]);
  }
  free(kyle.array);
}

Alright, so this code works, and does what it is supposed to (I was just messing around with structs to get a feel for them since I have never really used them before)

However, if in the part where I free the memory allocated for array, I use j instead of i, I get a segfault. Why would it matter which one of the indices I use, since I initialize it to 0 at the start and hard code the limits?

ie, if the bolded section above is replaced with

Code:

  for (j = 0; j < 5; j++)
  {
    free(kyle.array[i]); AHA! where did that i come from... ^_^
  }
  free(kyle.array);

it segfaults. Now I am sure this is just a trivial little thing I am missing, but I can't seem to see it.


EDIT: and I just saw it. Ignore me...

In the first loop your are freeing kyle.array[0,1,2,3,4], but in the next one you are freeing kyle.array[0] 5 times.