c permutation and combination with frequency
I have 2 strings where I have saved fixed 20 characters and these are A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T and same 20 char in string 2. so I will get 400 combinations of 2 character sets like
AA,AB,AC,AD,AE,AF,
AT
BA,BB,BC,BD,BE,BF,
..BT
CA,CB,CC,CD,CE,CF
CT
Code:
#include<stdio.h>
#include<conio.h>
#include<string.h>
int main()
{
int count = 0;
char sequence1[30] = "ACDEFGHILPNQYWRKMTSV";
char sequence2[30] = "ACDEFGHILPNQYWRKMTSV";
const char sequence3[30] = "AAGACDF"; /*sequence taken from user which will be of length 31*/
printf(" %s %s \n ",sequence1,sequence2);
for (int i=0; i<strlen(sequence1); i++)
{
for(int j=0;j<strlen(sequence2);j++)
{
printf(" %c %c",sequence1[i],sequence2[j]);
for(int k=0; k < strlen(sequence3)-1; k++)
{
if(sequence3[k] == sequence1[i] && sequence3[k+1] == sequence2[j])
{
//cout<<"(equal)\t";
count++;
}
}
}
}
printf("the number of matches are found %d ",count);
getch();
}
This way we will get 400 combinations (Which program I have created successfully) but then user will put the value till 31 characters witch will be treated as 3rd string for E.g. ABCDDAAAB now I have to check the frequency of user input in the sequence of 12,23,34,45,56,67,78,89 (2 CHAR SET) means AB,BC,CD,DD,DA,AA,AA,AB and need to show the frequency
of user input
OUTPUT:
AB=2
BC=1
CD=1
DD=1
DA=1
AA=2
