Thread: C programming Language

Write a program in C Program to find the sum of the following :
The input contain a sequence of two or more positive integers terminated by -1. Write a piece of code to count the ‘incidences’ in this sequence (i.e the number of pairs of equal, adjacent numbers). For example, the following sequence contains 4 incidences:
4 2 9 9 3 7 7 7 3 3 -1

i've write and please check for me

main()
{
int a,p,j;
scanf("%d %d %d",&a,&p,&j);

if (a==p)
printf("The number of pairs of equal is equal to 1 \n");

if (p==j)
printf("The number pairs of equal is equal to 1 \n");
else

if (a==p&&p==j)
printf("contain 2 incidences \n");
}

Output :
1
1
9
the number of pairs of equal to 1
Press any key to continue

That's the general idea. However you are only reading 3 numbers. You need to read a unknown number of numbers and only stop when you encounter -1. So you need a loop for that like so:

Code:

int nr_to_be_read = 0;

do{

 /* read number */
scanf("%d", &nr_to_be_read);

}while(nr_to_be_read != -1); /*until the number read will be -1 */

Also please don't open multiple threads on the same problem. Admins will probably merge these.