char *fun ()

Code:

char *fun (void)
{
 char str [30];

 fgets (str, 30, stdin);

 return str;
}

Is this wrong?

Isn't it possible to return a pointer to a local variable?

I get a warning when compiling.

It is better to do:

Code:

int fun(char *str)
{
 fgets(str,30,stdin);
 return 0;
}

saves memory, use it like this:

Code:

fun(string);

once that command is done, string will be set to whatever was input.

char str [30];

local variables only exist in the function they are declared in, so str will cease to exist when your function exits. Therefore you are returning a pointer to nothing.
What you need to do is declare str as static, this means it will remain in memory.

Code:

char *fun (void)
{
 static char str [30];

 fgets (str, 30, stdin);

 return str;
}

Or do as Brian said.

Thank you, guys !