A question about string

If I have a string like this:

char myString [5];

But I didn't put any characters into the array
does it mean:

myString [0] = '\0'
myString [1] = '\0'
myString [2] = '\0'
myString [3] = '\0'
myString [4] = '\0'

????

No. It means you can't know for sure what it does contain until you initialize it to something.

Originally Posted by winggx

If I have a string like this:

char myString [5];

But I didn't put any characters into the array
does it mean:

myString [0] = '\0'
myString [1] = '\0'
myString [2] = '\0'
myString [3] = '\0'
myString [4] = '\0'

????

no...
your array contains garbage and so cannot be used as string till you initialize it...

the simplest way to initialize string will be

Code:

char myString [5] = "";

the alternative is

Code:

char myString [5] =  {0};

yep, vart said it right. but just a note:

Code:

myString [0] = '\0'
myString [1] = '\0'
myString [2] = '\0'
myString [3] = '\0'
myString [4] = '\0'

inside of doing that, you could simple use the first line of code. since
C stops processing a string after reaching the \0 sign.

How about following code?

Code:

 
static char myString [5];

Regards,
Siddu

Originally Posted by Siddu_Kyocera

How about following code?

myString would have static storage duration, thus it would be zero initialised.

As long as the string is defined globally, it's same as static and is initialized to zeroes. If it's defined inside a function then its memory is the stack. It is not zeroed out when the function is executed.