Diffuculty with 2D arrays and print,fprintf

Hi,
I am having diffuculty with 2D arrays and printf, I am using a 3*17 array to store 3 strings 17 characters long. When I use printf it prints all 3 strings e.g.

Code:

for(j=0;j<3;j++)
printf("error: %s\n",error[j]);

The desired output would be someting like
error: 100000000000000000
error: 010000000000000000
error: 001000000000000000

However I get,
The desired output would be someting like
error: 10000000000000000001000000000000000000100000000000 0000
error: 010000000000000000001000000000000000
error: 001000000000000000
Any ideas what causes this and how to get what I want,
Cheers
I have a simaler problem with fprintf.

> I am using a 3*17 array to store 3 strings 17 characters long.
A string with 17 chars needs 18 bytes to store it, if you want to add a \0 on the end.

A C-string is a char array whose final element is '\0'.

A char array could be just any sequence of characters. So a C-string is a specific form of array (it's "null terminated").

I tried adding the extra null character by:

Code:

for(j=0;j<3;j++)
error[j][18]= '\0';

and the output was
error: 10000000000000000
error: 01000000000000000|}01000000000000000
error: 001000000000000000|}

A seventeen byte array begins with [0] and ends with [16].
An eighteen byte array begins with [0] and ends with [17].
A nineteen byte array begins with [0] and ends with [18].

If you printf an array with a '\0' in it as a %s, the output will end at the '\0'. There is no other possibility, besides a computer possessed by aliens, etc.

Maybe you should write as short an example of this as you can (you should be able to do it in < 10 lines) and then post the code so we can see what you are doing wrong.

Your right I should have written

Code:

for(j=0;j<3;j++)
error[j][17]= '\0';

That solves my problem and makes sense; Cheers.