Variable / Dynamic Paths in C

**Leo2010** · 02-27-2010

Hi all,

Im trying to use a variable as a path in C. For instance, the user enters a directory and this is used with the '*.*' notation attached so the program loops all files in the directory. I've got the PHP part of this code working in a separate part of the program but dont seem to be able to get it working in C. I've attached the example code below, any ideas?

Thank you for your time,

Code:

const char directory[50];

printf("Please enter directory to open: \n");
scanf("%s@, directory);

const char directoryfile[60] = "directory\\*.*";

do
{
....

If the user entered C:\Test as the directory
then
the directoryfile should become "C:\Test\file1.doc" etc.

Thanks again

**karthigayan** · 02-27-2010

I don't know why you are doing these many things to get the files in the directory and print the file names with its full path.

You can do this by opendir and readdir functions.I have developed this code in linux environment.

Code:



#include <sys/stat.h>
#include <stdlib.h>
#include <stdio.h>
#include<unistd.h>
#include <dirent.h>
DIR *db;
struct dirent *dirp;

main()
{
        char directory[50];
        printf("Enter the directory name : ");
        scanf("%s",directory);
if((db=opendir(directory))!=NULL)
{
        while((dirp=readdir(db))!=NULL)
        {
                printf("file name : %s/%s \n",directory,dirp->d_name);
        }
}
else
{
        printf("Can not open directory\n");
}
}

Thanks

**Leo2010** · 02-27-2010

Hi, thanks for your reply and example code.

Great suggestions, but i'd like to read in each file in turn as an array and search for a string of characters before moving onto the next. I've got that part of the code working with is just the sub function part but can't get create a variable using another variable + *.* at the end.

Is there a similar way for me to use the same methodology with your method shown in example code?

Thank you for your time

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