How do I input and print out a list of names

artistunknown · 02-09-2010, 07:48 PM

I have this code that it starts with a simple menu I can enter some names up to five and then have a choice to print out the names I'm using a multi dimensional array but I can't figure out how to display the names I think there store in there just not sure here's the code

Code:

#include <stdio.h>
#include <stdlib.h>

int main()
{

	int i = 0;
	char *iName[1][4] =  {'\0'};
       int iChoice = 0;


	while(iChoice != 3)
	{
		system("cls");
		printf("\n1\tEnter a name");
		printf("\n2\tPrint Report");
		printf("\n3\tQuit");
		printf("\n\n\tEnter a Choice: ");
		scanf("%d", &iChoice);

		if(iChoice == 1)
		{
			system("cls");
			printf("\n\tEnter a name: ");
			scanf("%s %s", iName[0],iName[1]);
		}
		else if(iChoice ==2)
		{
			break;

		}
		else if(iChoice == 3)
			break;
	}
	system("cls");
	for (i = 0; i <= 4; i++)
		printf("%s %s",iName[0],iName[1]);

}

Cameron2 · 02-09-2010, 08:15 PM

char *iName[1][4] is a mulidimensional array of pointers to chars. Why not just have an array of pointers to chars like this:

Code:

char *iName[4] //This will store 4 pointers to chars (4 strings)

Then you can do this:

Code:

if(iChoice == 1)
		{
			system("cls");
			printf("\n\tEnter a name: ");
			scanf("%s", iName[0]) //Store the first string;
		}

I'm sure you will be able to figure out the rest.

artistunknown · 02-09-2010, 08:24 PM

Well I might be able to figure that out but I'm suppose to learn how to use a multdimensional array the program is suppose to teach me how to use them

Cameron2 · 02-09-2010, 08:46 PM

Fair enough. I still don't see why you need a multidimensional array of pointers to chars, how about you just do this:

Code:

char iName[Number of Strings you want - 1][Length of string + 1]

Thus the definition:

Code:

char iName[1][4];

Creates 2 arrays of 5 chars.

02-09-2010, 08:15 PM	#2
Cameron2 Registered User Join Date: Feb 2010 Posts: 4	char iName[1][4] is a mulidimensional array of pointers to chars. Why not just have an array of pointers to chars like this: Code: char iName[4] //This will store 4 pointers to chars (4 strings) Then you can do this: Code: if(iChoice == 1) { system("cls"); printf("\n\tEnter a name: "); scanf("%s", iName[0]) //Store the first string; } I'm sure you will be able to figure out the rest.
Cameron2 is offline

02-09-2010, 08:24 PM	#3
artistunknown Registered User Join Date: Jan 2010 Posts: 54	Well I might be able to figure that out but I'm suppose to learn how to use a multdimensional array the program is suppose to teach me how to use them
artistunknown is offline

02-09-2010, 08:46 PM	#4
Cameron2 Registered User Join Date: Feb 2010 Posts: 4	Fair enough. I still don't see why you need a multidimensional array of pointers to chars, how about you just do this: Code: char iName[Number of Strings you want - 1][Length of string + 1] Thus the definition: Code: char iName[1][4]; Creates 2 arrays of 5 chars.
Cameron2 is offline

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