easyquestion

what is the difference between thank you for you help

Code:

char name[50],a ;


scanf("%s",name);

scanf("%s",name[i]);  // why is this syntex invalid


gets(name);


name[a]=getch(); //what is this mean iam i getting a string or array?

Code:

scanf("%s",name[i]);  // why is this syntex invalid

scanf is looking for a string not an array of char. meow.

Code:

name[a]=getch(); // how do i show the value the i have imput to the user in the screen.

if i understand you correctly

Code:

printf("%s",name);

should work.

>>scanf("%s",name);
Reads a string from the user into the array name (correct). Unsafe. Read SourceForge.net: Scanf woes - cpwiki

>>scanf("%s",name[i])
Incorrect. Tries to read a string from the user into a char whose value has been converted into an address. Double wrong. Plus "i" isn't declared anywhere. Scanf needs a pointer to a buffer where it needs to store the data. A char is not a pointer.

>>gets(name);
Worst thing to do. Ever. Read SourceForge.net: Gets - cpwiki

Furthermore, "a" is a char, yet you use it as an index. Is this intentional? Usually, an integer is used for such purposes, since, by definition, an array contains n elements of integer nature.

this sysntax does work

scanf("%s",name[i])

Originally Posted by mouse666666

this sysntax does work

No, because name is a pointer to a char array, which is where you would put a string (%s). name[i] would be an element of name, which would be where you would place a single letter (%c).

Since i is totally undefined, I am guessing you are cutting and pasting code. This may seem like a clever idea, but it is actually the least effective way to figure something out. If there were absolutely no documentation or way for you to read about and learn C syntax, then you would be left throwing darts blindfolded by cutting and pasting experimentation. But fortunately there is lots and lots of tutorials, etc, etc, around, so you don't have to do that.